The sidereal period of the Moon is the time needed for it to return to the same position against the background of stars. The Moon appears to move completely around the celestial sphere once in about 27.3 days as observed from the Earth. This is called a sidereal month. It represents the orbital period of the Moon around the Earth.

Question: In the table below we have provided the orbital distances, orbital periods, and masses for the six planets closest to the Sun. Orbital Distance Orbital Period Planet Mercury Venus Earth Mars Jupiter Saturn (in astronomical units - AU) 0.38 0.72 1.0 1.52 5.20 9.54 (in years) 0.24 0.61 1.0 1.88 11.86 29.46 Planet' Mass (in units of Earth's mass) 0.06 0.82

What are the orbital period and velocity of an astronaut in orbit at 300 km altitude? What is the orbital period of a satellite in geosynchronous orbit (r = 6.6 re)? How long does it take the Moon to orbit Earth if it is at 60 re from the center of Earth? (Use k = 1.69 and Kepler's third law with period (T) in hours and semi-major axis (a) in re.)

Question: (e) Enter Mercury's orbital period to confirm that the Calculator returns the planet's a value. Then, complete the following table for the solar system's eight planets. Name Period P (yr) Semimajor Axis a (AU) Mercury 0.241 0.387 Venus 0.723 Earth 1.00 Mars 1.881 1.524 Jupiter 5.203 Saturn 29.46 9.539 Uranus 84.01 Neptune 164.8 30.06 ...

The dwarf planet Pluto has an elliptical orbit with a semi-major axis of 5.91×1012 m and eccentricity 0.249. A) Calculate Pluto's orbital period. Express your answer in seconds B) Calculate Pluto's orbital period. Express your answer in earth years C) During Pluto's orbit around the sun, what are its closest distance from the sun?

The graph below illustrates how the orbital period (expressed in years) and orbital distance (expressed in years) and orbital distance (expressed in astronomical units, AU) of a planet are related. 1. According to the graph, would you say that the orbital period of planets appears to increase, decrease, or stay the same as their orbital distance is

Question: Question 21 (2 points) Suppose a new planet was found in our Solar System that orbited with a semimajor axis of (average distance) 4.0 AU from the Sun. Using Kepler's Third Law, calculate its orbital period. 04.0 years O 8 years O 64 years O 128 years Question 22 (2 points) Suppose a planet was discovered way out at 121 AU from the Sun.

Question: Kepler's Third Law in the table below we have provided the orbital distances, orbital periods, and masses for the six planets closest to the Sun. Planet Orbital Period (in years) Orbital Distance (in astronomical units-AU) 0.38 0.72 Mercury Venus Earth Mars Jupiter Saturn 1.0 Planet Mass (in units of Earth's mass) 0.06 0.82 1.0 0.11 318 95.2 0.24 0.61 1.0

Question: Exoplanet Distance Once we have the orbital period of the exoplanets, we can calculate the distance of the exoplanet from the star that it orbits. Distance[AU]=(365 Orbital Period [days] )2/3 Note: you can use Google to do this calculation. For example, if your period is 100 days, just enter? (100/365)∧(2/3) into Google to get 0.42.

The dwarf planet Sedna has an orbital period of about 11,400 years. Approximately how often should Sedna be at opposition from Earth's perspective? a. Once every 11,400 years. b. Once every 5700 years. c. Once every year. d. Each night. e. Always. f. Never